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Mahāsattva

From Tibetan Buddhist Encyclopedia
(Redirected from Móhé sāduò)
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Mahāsattva, Sanskrit word belonging to the vocabulary of Mahāyāna Buddhism, meaning literally "great being", is a great Bodhisattva practicing the Buddhism for a long time and reaching a very high level on the path to awakening (bodhi), generally refers to the Bodhisattvas who have reached at least the seventh ground of the ten Bodhisattvas' grounds (bodhisattvānām daśabhūmīḥ).

The translation of the word Mahāsattva in Chinese is móhé sāduò 摩诃萨埵 (often simplified in móhésà 摩诃萨) and dàshì 大士, in Japanese, makasatsu or daishi.

The eight most famous Mahāsattvas are Mañjuśrī, Samantabhadra, Avalokiteśvara, Mahāsthāmaprāpta, Âkāśagarbha (Akasagarbha), Kṣitigarbha, Maitreya and Sarvanīvaraṇaviṣkambhin (Sarvanivarana-Vishkambhin).

Mahasattva.

Source

Wikipedia:Mahāsattva